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一元二次解方程

3x + 6x - 4 =0解:9x=4x=4/93x(x+1)=3x+3解:3x^2+3x=3x+3x^2=1x1=1或x2=-14x - 4x + 1 = x + 6x + 9解:7x=-8x=-8/77x - ∫16 - 5 = 0

3x + 6x - 4 =0

解:9x=4

x=4/9

3x(x+1)=3x+3

解:3x^2+3x=3x+3

x^2=1

x1=1或x2=-1

4x - 4x + 1 = x + 6x + 9

解:7x=-8

x=-8/7

7x - ∫16 - 5 = 0 是16的开方吗?若是得

7x-4-5=0

7x=9

x=9/7

x - x - 1 = 0的确有问题