一元二次解方程
•
民间故事
3x + 6x - 4 =0解:9x=4x=4/93x(x+1)=3x+3解:3x^2+3x=3x+3x^2=1x1=1或x2=-14x - 4x + 1 = x + 6x + 9解:7x=-8x=-8/77x - ∫16 - 5 = 0
3x + 6x - 4 =0
解:9x=4
x=4/9
3x(x+1)=3x+3
解:3x^2+3x=3x+3
x^2=1
x1=1或x2=-1
4x - 4x + 1 = x + 6x + 9
解:7x=-8
x=-8/7
7x - ∫16 - 5 = 0 是16的开方吗?若是得
7x-4-5=0
7x=9
x=9/7
x - x - 1 = 0的确有问题